3cos^2x+4sinx+1=0

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Solution for 3cos^2x+4sinx+1=0 equation:


Simplifying
3cos2x + 4sinx + 1 = 0

Reorder the terms:
1 + 3cos2x + 4insx = 0

Solving
1 + 3cos2x + 4insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 3cos2x + -1 + 4insx = 0 + -1

Reorder the terms:
1 + -1 + 3cos2x + 4insx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3cos2x + 4insx = 0 + -1
3cos2x + 4insx = 0 + -1

Combine like terms: 0 + -1 = -1
3cos2x + 4insx = -1

Add '-4insx' to each side of the equation.
3cos2x + 4insx + -4insx = -1 + -4insx

Combine like terms: 4insx + -4insx = 0
3cos2x + 0 = -1 + -4insx
3cos2x = -1 + -4insx

Divide each side by '3os2x'.
c = -0.3333333333o-1s-2x-1 + -1.333333333ino-1s-1

Simplifying
c = -0.3333333333o-1s-2x-1 + -1.333333333ino-1s-1

Reorder the terms:
c = -1.333333333ino-1s-1 + -0.3333333333o-1s-2x-1

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